37.
[tex]7 < \sqrt{50} < 8[/tex]
Because:
[tex](\sqrt{50})^2=50\\\\7^2=49 < 50\\\\8^2=64 > 50\\\\49 < 50 < 64[/tex]
Answer: 7 and 8.
38.
We have two triangles and a square.
The formula of an area of a triangle: [tex]A=\dfrac{bh}{2}[/tex]
[tex]\triangle_1:\\b=6in,\ h=6in\\\\A_{\triangle_1}=\dfrac{6\cdot6}{2}=18\ in^2\\\\\triangle_2:\\b=6in,\ h=6in\\\\A_{\triangle_2}=\dfrac{6\cdot6}{2}=18\ in^2[/tex]
The formula of an area of a square: [tex]A=a^2[/tex]
[tex]square:\\a=6in\\\\A_S=6^2=36\ in^2[/tex]
The area of the figure:
[tex]A_F=A_{\triangle_1}+A_{\triangle_2}+A_S\\\\A_F=18+18+36=72\ in^2[/tex]
