Respuesta :

9.8 × 17 / 22.4 = 7. 44g

Answer: The mass of ammonia will be 7.34 g

Explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

[tex]PV=nRT[/tex]

Or,

[tex]PV=\frac{m}{M}RT[/tex]

where,

P = pressure of the gas = 100 kPa

V = Volume of gas = 9.8 L

m = Given mass of ammonia = ? g

M = Molar mass of ammonia = 17 g/mol

R = Gas constant = [tex]8.31\text{L kPa }mol^{-1}K^{-1}[/tex]

T = temperature of the gas = 273 K

Putting values in above equation, we get:

[tex]100kPa\times 9.8L=\frac{m}{17g/mol}\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 273K\\\\m=7.34g[/tex]

Hence, the mass of ammonia will be 7.34 g