Respuesta :
Question 1:
A large circular pizza that is divided into eight equal slices.
Circumference of a whole pizza (circle) = [tex] 2\Pi r [/tex]
Since a pizza is divided into 8 equal parts.
So, circumference of 1 part = [tex] \frac{2\Pi r}{8} [/tex] = [tex] \frac{\Pi r}{4} [/tex] inches
The measure of outer edge of the crust of one piece = 5.5 inches.
[tex] \frac{\Pi r}{4} = 5.5 [/tex]
[tex] r = \frac{5.5 \times 4}{\Pi } [/tex]
[tex] r = \frac{22}{\Pi } [/tex]
[tex] r = 22 \times \frac{7}{22} [/tex]
r = 7 inches
Therefore, diameter = 2r = 2 [tex] \times [/tex] 7 = 14 inches.
Question 2:
Given length = 15 in
Breadth= 4 in
height = 5 in
We have to determine the surface area of rectangular prism.
Surface area of rectangular prism = [tex] 2 \times (lb+bh+hl) [/tex]
= [tex] 2 \times ((15 \times 4)+ (4 \times 5) + (15 \times 5)) [/tex]
=[tex] 2 \times (60+ 20 +75) [/tex]
= 2 [tex] \times [/tex] 155 [tex] in^{2} [/tex]
= 310[tex] in^{2} [/tex]
So, the surface area of rectangular prism is 310[tex] in^{2} [/tex].
