Respuesta :
So firstly, let's solve the expressions when t = 3 and t = 7
First expression:
[tex] 6(3)+12\\ 18+12\\ 30 [/tex]
[tex] 6(7)+12\\ 42+12\\ 54 [/tex]
Second expression:
[tex] 6(3+2)\\ 6(5)\\ 30 [/tex]
[tex] 6(7+2)\\ 6(9)\\ 54 [/tex]
Also note that if we foil the second expression, it is the same as the first expression.
So all that apply are:
- The value of both expressions when t = 3 is 30
- The value of both expressions when t = 7 is 54
- The expressions are equivalent