Respuesta :

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The rule of a geometric sequence:

[tex] a_n=a_1r^{n-1} [/tex]

We have:

[tex]a_1=;\ r=-\dfrac{2}{3}[/tex]

Find

[tex]a_7=?\to n=7[/tex]

substitute

[tex]a_7=1\cdot\left(-\dfrac{2}{3}\right)^{7-1}=\left(-\dfrac{2}{3}\right)^6=\dfrac{64}{729}[/tex]

A geometric progression has the same ratio between two consecutive terms. The seventh term of the geometric progression is 64/729.

What is a geometric sequence and how to find its nth terms?

Suppose the initial term of a geometric sequence is a

and the term by which we multiply the previous term to get the next term is r, Then the sequence would look like

[tex]a, ar, ar^2, ar^3, \cdots[/tex]

(till the terms to which it is defined)

Thus, the nth term of such sequence would be [tex]T_n = ar^{n-1}[/tex](you can easily predict this formula, as for nth term, the multiple r would've multiplied with initial terms n-1 times).


Given the first term of the geometric progression is a₁=1. Also, the common ratio between the two terms is r= -(2/3). Therefore, the seventh term will be,

a₇ = a₁ × r⁽ⁿ⁻¹⁾

a₇ = 1 × -(2/3)⁶

a₇ = (64/729)

Hence, the seventh term of the geometric progression is 64/729.

Learn more about Geometric sequence:

https://brainly.com/question/2735005

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