A town predicts that its population will double in e ^ In 10/ 2 In e years.

Simplify the expression. In how many years will the population of the town double?

Respuesta :

[tex] \dfrac{e^{\ln 10}}{2\ln e}=\dfrac{10}{2}=5 [/tex]

Answer: 5 years

Step-by-step explanation:

Given : A town predicts that its population will double in [tex]\dfrac{e^{\ln10}}{2\ln_e}[/tex] years.

We know that [tex]e^{\ln x}= x[/tex]

and the natural log of e = [tex]\ln_e=1[/tex]

Then , the expression  [tex]\dfrac{e^{\ln10}}{2\ln_e}[/tex] will becomes

[tex]\dfrac{10}{2}=5[/tex]

Hence, The population of the town will be double in 5 years.