Respuesta :

[tex] P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\
|\Omega|=9\cdot8=72\\
|A|=4\cdot8=32\\
|A\cap B|=4\cdot3=12\\\\
P(A)=\dfrac{32}{72}=\dfrac{4}{9}\\
P(A \cap B)=\dfrac{12}{72}=\dfrac{1}{6}\\\\
P(B|A)=\dfrac{\dfrac{1}{6}}{\dfrac{4}{9}}=\dfrac{1}{6}\cdot\dfrac{9}{4}=\dfrac{3}{8}\Rightarrow \text{A} [/tex]