A. 7/16
B. 7/15
C. 14/16
D. 14/15
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[tex] P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\
|\Omega|=16\cdot15=240\\
|A|=5\cdot15=75\\
|A\cap B|=5\cdot7=35\\\\
P(A)=\dfrac{75}{240}=\dfrac{5}{16}\\
P(A \cap B)=\dfrac{35}{240}=\dfrac{7}{48}\\\\
P(B|A)=\dfrac{\dfrac{7}{48}}{\dfrac{5}{16}}=\dfrac{7}{48}\cdot\dfrac{16}{5}=\dfrac{7}{15}\Rightarrow \text{B }[/tex]
Ok so P(B/A) is equal to Event B = 3/16 divided by Event A = 5/16
Event B = 3/16 Since P(not getting blue) = 12/16 = 3/4 times P(getting blue on second turn) = 4/15
4/15 times 3/4 = 12/60 = 1/5
Now we divide 1/5 by 5/16
1/5 / 5/16 =
1/5 x 16/5 =
16/25=
Hope this helps!