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(06.01) In the below system, solve for y in the first equation. x + 3y = 6 2x − y = 10 one thirdx + 2 negative one thirdx + 6 −x + 2 negative one thirdx + 2

Respuesta :

calculista

we have that

x + 3y = 6 -------> first equation

2x − y = 10


x + 3y = 6-----> substract x both sides

-x+x+3y=6-x

3y=6-x-----> divide by 3 both sides

y=(6-x) /3

y=2-(x/3)

y=-(x/3)+2

therefore


the answer is

negative one thirdx + 2

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