Respuesta :

konrad509

[tex] \dfrac{1}{2} x-3=\dfrac{2}{3}(x-1)|\cdot6\\
3x-18=4(x-1)\\
3x-18=4x-4\\
4x-3x=-18+4\\
x=-14
[/tex]

SvetkaChem

[tex] \frac{1}{2} x - 3 = \frac{2}{3} (x-1)
\\ \\\frac{1}{2} x - 3 = \frac{2}{3}x-\frac{2}{3}
\\ \\\frac{2}{3} - 3 = \frac{2}{3}x- \frac{1}{2} x
\\ \\\frac{2}{3} - \frac{9}{3} = \frac{2*2}{3*2}x- \frac{1*3}{2*3} x\\
\\-\frac{7}{3} =\frac{1}{6} x
\\ \\-\frac{7}{3}*6 =\frac{1}{6} x*6
\\ \\ x=-14 [/tex]

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