For this case we have the following function:
[tex] y=\frac{3}{4}x^2 [/tex]
When evaluating x = 2 in the given function we have:
[tex] y=\frac{3}{4}(2)^2 [/tex]
Rewriting we have:
[tex] y=\frac{3}{4}(4) [/tex]
[tex] y=3 [/tex]
Therefore, the pair ordered for this point is given by:
[tex] (x, y) = (2,3)
[/tex]
The ordered pair of the table for x = 2 is:
[tex] (x, y) = (2,4)
[/tex]
Therefore, the table is incorrect for x = 2
Answer:
The row in the table is incorrect for:
x=2
