Respuesta :

kenmyna

The volume of 2.75 M solution of NaOH required to make 500.0 ml of a 1.27M solution of NaOH is 230.9 Ml


calculation


by use of M1V1=M2V2 volume formula where


M1=2.75 m

V1=?

M2= 500 Ml

V2= 1.27 M


make V1 the subject of the formula V1= M2V2/M1


V1 is therefore= 500Ml x 1.27 M/ 2.75 M = 230.9 Ml

sebassandin

Answer:

[tex]V_1=230.9mL[/tex]

Explanation:

Hello,

This is about a dilution exercise which could be mathematically solved by taking into account that during the dilution process the moles are conserved:

[tex]n_1=n_2[/tex]

Now, as the moles could be expressed in term of molarity an volume one defines:

[tex]M_1V_1=M_2V_2[/tex]

Then, we're asked to report [tex]V_1[/tex] as it is the volume we need to take from the inital 2.75M solution of NaOH, thus:

[tex]V_1=\frac{M_2V_2}{M_1} =\frac{1.27M*500.0mL}{2.75M}\\V_1=230.9mL[/tex]

Best regards.

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