Respuesta :

kanest

In a parallelogram, the opposite angles will be congruent to each other.


In this parallelogram, angles B and C are congruent, and angles A and D are congruent.


We will work on angles B and C first. Set the two angles to equal each other:


[tex] 12x + 6 = 6x + 66 [/tex]


Subtract 6 from both sides:


[tex] 12x = 6x + 60 [/tex]


Subtract 6x from both sides:


[tex] 6x = 60 [/tex]


Divide both sides by 6 to get x by itself:


[tex] \boxed{x = 10} [/tex]


x will equal 10.


Set angles A and D to equal each other:


[tex] 54 = 3y [/tex]


Divide both sides by 3 to get y by itself:


[tex] \boxed{y = 18} [/tex]


y will equal 18.


The x and y values that make this quadrilateral a parallelogram will be x = 10, and y = 18.