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Radio signals travel at a rate of 3 × 10^8 meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 7.5 × 10^6 meters?

Respuesta :

jcherry99

This question is an example of d = r * t

r = rate

r = 3*10^8 m/s

t = ??

d = 7.5 * 10^6 meters.


Sub and solve

d = r * t

7.5 * 10^6 = 3 * 10^8 * t Divide both sides by 3 * 10^8


7.5 * 10^6 / (3 * 10^8) = t

2.5 * 10^(6 - 8) = t

2.5 * 10^-2 seconds = t or

0.025 seconds = t

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