SOMEONE HELP OUT I DONT HAVE MUCH TIME
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To solve this problem you must apply the proccedure shown below:
1. If both lines are parallel, they have the same slope ([tex] m=3 [/tex])
2. You have that the equation of the line is:
[tex] y=mx+b [/tex]
Where [tex] m [/tex] is the slope and [tex] b [/tex] is the y-intercept.
3. You know that the other line must pass through the point ([tex] 1,8 [/tex]). So, you can solve for [tex] b [/tex] to calculate its value, as following:
[tex] 8=3(1)+b\\ b=5 [/tex]
4. Therefore, the equation of the line that is parallel to [tex] y=3x-8 [/tex] is
[tex] y=3x+5 [/tex]
The answer is: [tex] y=3x+5 [/tex]