EXTRA POINTS AND BRAINLIEST ANWSER IF YOU HELP !!! APPROPRIATE ANWSERS ONLY !!
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[tex]\sin \angle FHG = \dfrac{FG}{FH}[/tex]
[tex]FH = \dfrac{FG}{\sin \angle FHG}[/tex]
[tex]EF^2 + FH^2 = EH^2[/tex]
[tex]\cos \angle FHE = \dfrac{FH}{EH}[/tex]
We have all the pieces we need.
[tex]FH = \dfrac{FG}{\sin \angle FHG} = \dfrac{\sqrt{8}}{1/\sqrt{2}}=\sqrt{16}=4[/tex]
[tex]EH= \sqrt{ EF^2 + FH^2} = \sqrt{3^2 + 4^2}=5[/tex]
[tex]\cos \angle FHE = \dfrac{FH}{EH} = \dfrac 4 5[/tex]
It's nice when the numbers work out.
Answer:
\cos \angle FHE = \dfrac{FH}{EH} = \dfrac 4 5
It's nice when the numbers work out.
Step-by-step explanation: