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f the resistance remains constant and the voltage doubles, what effect will that have on the power? 
A.The power will remain the same.
B.The power will decrease by a factor of 2.
C.The power will decrease by a factor of 4.
D.The power will increase by a factor of 2.
E.The power will increase by a factor of 4

Respuesta :

feynman135
P = I^2R= V*I = V(V/R)= V^2/R. Substitute V with 2V and p=(2V)^2/R = 4V^2/R, so power quadruples which is E

Answer:

The power will increase by a factor of 4

E is correct.

Explanation:

Given that,

The power of the circuit in form of voltage

[tex]P=\dfrac{V^2}{R}[/tex]

If the resistance remains constant then

[tex]P\proto V^2[/tex]

using this equation we will compare P and V

[tex]\dfrac{P_1}{P_2}=\dfrac{V_1^2}{V_2^2}[/tex]

Where,

[tex]P_1=P[/tex]

[tex]V_1=V[/tex]

[tex]V_2=2V[/tex]

Now, we substitute the value into formula  and we get

[tex]\dfrac{P}{P_2}=\dfrac{V}{(2V)^2}[/tex]

[tex]\dfrac{P}{P_2}=\dfrac{1}{4}[/tex]

[tex]P_2=4P[/tex]

Hence, The power will increase by a factor of 4

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