In triangle ABC below, sinC=h/a and sinA=h/c. Which of the following combines the two sine ratios into one equation?

A. asinC=csinA
B. hsinC=hsinA
C. h/sinC=h/sinA
D. sinC/a=sinA/c

In triangle ABC below sinCha and sinAhc Which of the following combines the two sine ratios into one equation A asinCcsinA B hsinChsinA C hsinChsinA D sinCasinA class=

Respuesta :

We know:

[tex]sin(C)=\frac{h}{a}[/tex]

and

[tex]sin(A)=\frac{h}{c}[/tex]


These expressions have an [tex]h[/tex] term in common. We can combine them if we can find forms of the expressions in terms of [tex]h[/tex]:

[tex]h=a(sin(C))[/tex]

[tex]h=c(sin(A))[/tex]


Now, because [tex]h=h[/tex] (by the reflexive property), we can write:


[tex]a(sin(C))=c(sin(A))[/tex]


This is our answer, A.

Answer:

A

Step-by-step explanation:

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