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12-07-2018
Mathematics

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Find the quotient of -40^3-12x^2+16x/-4x

a- 10x^2 + 3x − 4
b- −40x^3 − 12x^2 − 4
c- −10x^2 + 3x − 4
d- 10x^2 − 3x + 4

Respuesta :

19-07-2018

[tex] \dfrac{-40x^3-12x^2+16x}{-4x}=\dfrac{-40x^3}{-4x}+\dfrac{-12x^2}{-4x}+\dfrac{16x}{-4x}=10x^2+3x-4 [/tex]

Answer: a- 10x^2 + 3x - 4

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