Respuesta :

DeanR

The sector is [tex]\dfrac{360^\circ - 60^\circ}{360^\circ} = \dfrac 5 6 [/tex] of the circle so the area is


[tex]\dfrac 5 6 \pi r^2 = \dfrac 5 6 \pi (10^2) = \dfrac{250 \pi}{3}[/tex]