Answer:
Confidence Interval = (23.776, 24.224)
Step-by-step explanation:
Restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average.
⇒ Mean = 24 ounces.
Standard Deviation = 0.8
Number of bottles used for sample = 49
⇒ n = 49
Confidence level = 95%
Corresponding z value with 95% confidence level = 1.96
Now, confidence interval is given by the following expression :
[tex]Mean \pm z^*\times \frac{\sigma}{\sqrt{n}}\\\\=24\pm1.96\times \frac{0.8}{\sqrt{49}}\\\\=24\pm 0.224[/tex]
Hence, Confidence Interval = (23.776, 24.224)
