△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).

The distance between the x-coordinates of R and T is .
The distance between the y-coordinates of R and T is .
R' is from T, so the coordinates of R' are .

Respuesta :

ug2019

Answer:

△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).  The distance between the x-coordinates of R and T is 3. See below.

.

Step-by-step explanation:

Ver imagen ug2019

The values obtained from the dilation transformation are;

  • The distance between the x-coordinate of R and T is 3
  • The distance between the y-coordinate of R and T is 6
  • R' is (-1, 2) from T, so the coordinates of R' are (2, 0)

Reason:

The given rule for the dilation of ΔRST is [tex]D_{T, \, 1/3}(x, \, y)[/tex]

The vertices of the given triangle are R(0, 4), S(0, -2), T(3, -2)

The distance between the x-coordinate of R and T is 3 - 0 = 3

The distance between the y-coordinate of R and T is 4 - (-2) = 6

The location of the point R' relative to point T is therefore; [tex]\dfrac{1}{3} \times \left (-3, \, 6) = (-1, \, 2)[/tex]

Which gives the location of point R' = (-1 + 3, 2 - 2) = R'(2, 0)

Therefore;

R' is (-1, 2) from T, so the coordinates of R' are (2, 0)

Learn more here:

https://brainly.com/question/20958345

Ver imagen oeerivona