For this case we have the following diagonals.
Since it is a rectangle, then the length of the diagonals is the same.
We have then:
AC = BD
Substituting values we have:
[tex] 2 (5a + 1) = 2 (a + 1)
[/tex]
Rewriting:
[tex] 5a + 1 = a + 1
[/tex]
Clearing the value of a we have:
[tex] 5a-a = 1-1
4a = 0
a = 0/4
a = 0
[/tex]
Substituted the value of a in any of the equations we have:
[tex] 2 (a + 1) = 2 (0 + 1)
2 (a + 1) = 2 (1)
2 (a + 1) = 2
[/tex]
Answer:
The length of each diagonal is:
[tex] AC = BD = 2 [/tex]
