Answer:
Since, the equation of the line passes through the point [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex],
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Thus, the equation of the line that passes through the points (-3,7) and (6,4) is,
[tex]y-7=\frac{4-7}{6-(-3)}(x-(-3))[/tex]
[tex]y-7=\frac{-3}{6+3}(x+3)[/tex]
[tex]y-7=\frac{-3}{9}(x+3)[/tex]
[tex]y-7=-\frac{1}{3}(x+3)[/tex]
[tex]3y-21=-x-3[/tex]
[tex]\implies x+3y=18[/tex]
Graphing the line :
Since, the x-intercept of the line is (18,0)
And, the y-intercept of the line is (0,6)
