Given function is
[tex]f(x)=(x-2)^2+1[/tex]
Now question says to find the graph that shows the axis of symmetry for the given function.
Graph is missing but I can help you to find the correct graph.
Given equation is in the vertex form whose formula is given by
[tex]f(x)=a(x-h)^2+k[/tex]
Comparing given function with above formula, we get:
a=1, h=2 and k=1.
For the vertex formula [tex]f(x)=a(x-h)^2+k[/tex], we know that axis of symetry is given by equation:
x=h
So for the given function, axis of symmetry will be x=2
Graph of x=2 will be a vertical line crossing x-axis at x=2
So you just need to find the graph from given choices which contains a vertical line crossing x-axis at x=2.
