Respuesta :
x^2+y^2=z^2
x^2+96^2=100^2
x=sqrt(100^2-96^2)
x=28 so the distance from the base of the ladder and the base of the ladder is 28ft.
Hope this helps. Any questions please just ask. Thank you.
x^2+96^2=100^2
x=sqrt(100^2-96^2)
x=28 so the distance from the base of the ladder and the base of the ladder is 28ft.
Hope this helps. Any questions please just ask. Thank you.
Answer:
28 ft
Step-by-step explanation:
I add a graph to this question.
In the graph we can see that the ladder, the building and the distance ''x'' form a right triangle.
We can use the Pythagorean theorem to solve this exercise. The Pythagorean theorem states that if ''a'' and ''b'' are the sides of a triangle and 'h'' is its hypotenuse ⇒
[tex]a^{2}+b^{2}=h^{2}[/tex]
If we apply this equation to the graph we can find the distance ''x'' :
[tex]x^{2}+(96ft)^{2}=(100ft)^{2}[/tex]
[tex]x^{2}+9216(ft^{2})=10000(ft^{2})[/tex]
[tex]x^{2}=784(ft^{2})[/tex]
[tex]x=\sqrt{784(ft^{2})}[/tex]
[tex]x=28ft[/tex]
We find that the distance ''x'' is 28 ft
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