[tex]\dfrac{1}{2x+14}-\dfrac{9}{x+7}=-6\ \ \ \ \ /D:x\neq-7/\\\\\dfrac{1}{2(x+7)}-\dfrac{9}{x+7}=-6\ \ \ \ |\cdot2\\\\\dfrac{1}{x+7}-\dfrac{18}{x+7}=-12\\\\\dfrac{1-18}{x+7}=-12\\\\\dfrac{-17}{x+7}=\dfrac{-12}{1}\ \ \ \ |cross\ multiply\\\\-12(x+7)=-17\cdot1\\\\-12x-84=-17\ \ \ |+84\\\\-12x=67\ \ \ |:(-12)\\\\x=-\dfrac{67}{12}[/tex]
[tex]\text{Answer:}\ c.\ x=-\dfrac{67}{12}[/tex]
