Answer: The volume of alcohol present in 0.9 L of wine is 117 mL
Explanation:
We are given:
13 % alcohol by volume in wine.
This means that 13 mL of alcohol is present in 100 mL of wine.
We need to calculate the volume of alcohol in 0.9 L of wine.
Volume of wine = 0.9 L = 900 mL (Conversion factor: 1 L = 1000 mL)
By applying unitary method, we get:
In 100 mL of wine, volume of alcohol present is 13 mL
So, in 900 mL of wine, volume of alcohol present will be = [tex]\frac{13}{100}\times 900=117mL[/tex]
Hence, the volume of alcohol present in 0.9 L of wine is 117 mL
