a. The expression for the time t it takes to jog 5 miles from the park as a function of r, we shall proceed as follows:
time=(distance)/speed
time=t
distance=5 miles
speed=(r) miles per hour
plugging the values in the formula we get:
t=5/(r)
b. When you run back to the park, your average speed increases by 1 mph. Write an expression representing your new speed.
Given that on the way back, the speed increases by 1 mph, the expression representing new speed will be:
initial speed=r mph
new speed=r+1=(r+1) mph
c. Write an expression for the time t(in hours) it takes to jog 5 miles back to the park.
Here we shall use the formula:
Time taken for the jog 5 miles back to the park will be given by:
time=distance/speed
distance=5 miles
speed=(r+1) mph
thus
time=5/(r+1) hours
d. The expression for total jogging time will be given by:
Total time=5/r+5/(1+r)
=[5(1+r)+5r]/[r(1+r)]
=[5+5r+5r]/[r(1+r)]
=(5+10r)/[r(1+r)]
e] The total time of jogging given that r=4 mph will be:
plugging r=4 in the answer from (d) we get:
(5+10r)/[r(1+r)]
=(5+10*4)/[4(1+4)]
=(5+40)/(4(5))
=45/20
=2.25 hours