Determine the nature of the roots: 4x^2 + 32x + 64 = 0

a. no real solutions
b. a unique real solution
c. two distinct real solutions
d. cannot be determined

Respuesta :

Answer:

b. a unique real solution

Step-by-step explanation:

A quadratic equation ax² + bx + c = 0 ,

Has two distinct real roots,

If discriminant, [tex]D=b^2 - 4ac > 1[/tex]

Has two equal real roots,

If D = 0,

Has two imaginary roots or no real roots,

if D < 1,

Here. the given qudratic equation,

[tex]4x^2 + 32x + 64=0[/tex]

By comparing,

a = 4, b = 32, c = 64,

[tex]\implies D = 32^2 - 4\times 4\times 64 = 1024 - 1024 = 0[/tex]

Hence, the equation has two equal real roots or a unique real solution.

i.e. OPTION 'b' is correct.

Answer: B a unique real solution

Step-by-step explanation:

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