we have
y= x²------------> y = (x-10)²+8
we know that
f(x)+d------> a point (x,y) in f(x) becomes a----------> (x,y+d)----> shift up by d
and
f(x-e) ----> a point (x,y) in f(x) becomes a----------> (x+e,y)----> shift right by e
in this problem
d=8
e=10
therefore
Shift the graph of y = x²
up by 8 and right by 10
the rule is
(x,y)-------> (x+10,y+8)
let's check it
the vertex in y= x²-----------> (0,0)
the vertex in y = (x-10)²+8-----> (10,8)
so
(0,0)----------> (x+10,y+8)------> (0+10,0+8)-----> (10,8)------> is ok
the answer is
Shift the graph of y = x2 right 10 units and then up 8 units.
