[tex]y=\dfrac{3}{x-2}+6\\\\Draw:\ y=\dfrac{3}{x}\\\\shift\ 2\ units\ right\ and\ 6\ units\ up.[/tex]
[tex]y=\sqrt{x-2}+8\\\\Draw:\ y=\sqrt{x}\\\\shift\ 2\ units\ right\ and\ 8\ units\ up.[/tex]
The answer is the first coordinate of the intersection point of the graphs:
x = 3
