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A chemist makes a solution of NaOH for use in an experiment. She dissolves 0.00500 mol NaOH in 1.00 L H2O. The NaOH completely dissociates to form a solution with [OH− ] = 0.00500 M. What is the pH of the solution?

Respuesta :

Answer:

pH = 11.7

Explanation:

Given:

[OH-] = 0.00500 M

To determine:

pH of the solution

Explanation:

pH refers to the H+ ion concentration in a given solution whereas pOH indicates the OH- ion concentration.

pH and pOH are related by the following equation:

[tex]pH + pOH = 14 ------(1)[/tex]

Here:

[tex]pH = -log[H+]\\\\pOH = -log[OH-][/tex]

When OH- = 0.00500 M

[tex]pOH = -log(0.00500) = 2.30\\[/tex]

Based on equation(1):

[tex]pH = 14 - pOH = 14 -2.30=11.7[/tex]

madams43

Answer:

The pOH is 2.30 :D

Explanation:

taking the test/assignment on Edg. ;-P Hope this helps! UwU

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