Answer:
The correct option is 1. The axis of symmetry of the given graph is x=1.
Step-by-step explanation:
If a quadratic function is defined as
[tex]y=ax^2+bx+c[/tex] ... (1)
then, the axis of symmetry is
[tex]x=-\frac{b}{2a}[/tex]
The given parabolic equation is
[tex]y=2x^2-4x+4[/tex] .... (2)
On comparing (1) and (2), we get
[tex]a=2,b=-4,c=4[/tex]
The axis of symmetry of given graph is
[tex]x=-\frac{(-4)}{2(2)}[/tex]
[tex]x=-\frac{(-4)}{4}[/tex]
[tex]x=1[/tex]
Therefore the axis of symmetry of the given graph is x=1 and option 1 is correct.
