Using similarity of triangles, the value of m in the given right angle triangle ABC is √95.
In ΔABC and ΔBDC
∠B= ∠BDC =90°
∠C=∠C...Common Angle
So, ΔABC and ΔBDC are similar triangles.
What are similar triangles?
Similar triangles are triangles that are similar due to the equality of corresponding angles and the proportional similarity of the corresponding sides.
Since ΔABC and ΔBDC are similar triangles, corresponding sides will be in proportion.
i.e. [tex]\frac{AC}{m} = \frac{m}{DC}[/tex]
[tex]m^2 = AC.DC[/tex]
[tex]m = \sqrt{AC.DC}[/tex]
[tex]m =\sqrt{95}[/tex]
Therefore, the value of m in the given figure is √95.
To get more about similar triangles visit:
https://brainly.com/question/14285697
