The coordinate grid shows the graph of four equations:

A coordinate grid is shown from negative 12 to positive 12 on the x axis and also on the y axis. Line A passes through the ordered pairs negative 3, 4 and 9, negative 2. Line B passes through the ordered pairs 2, 8 and 8, negative 8. Line C passes through the ordered pairs negative 3, negative 4 and 4, 6. Line D passes through the points 2, negative 2 and 5 and 6.

Which set of equations has (3, 1) as its solution?

A and B
C and D
B and D
A and D

A line on a graph is the set of ordered pairs that satisfies the equation for the line. A system of linear equations will graph as multiple lines on the graph. Since each point on the line is a solution to the equation, a point where the lines intersect will be a solution to all of the equations whose lines intersect at that point. That is, the point of intersection is the solution to a system of equations.

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identifying the equations from the solution

We are asked to identify the equations for which the point (3, 1) is a solution. When we locate point (3, 1) on the grid, we find it is at the intersection of lines labeled A and D. Those are the designators for the equations that have the point (3, 1) as a solution.

Equations A and D have the point (3, 1) as a solution.

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Additional comment

The attached graph identifies the point (3, 1), and shows that the lines through that point are labeled A and D. Equations for lines A and D both have the point (3, 1) as their solution.

shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-06-08T16:26:54+02:00

The set of equations that has (3, 1) as its solution are lines A and D.

What is the slope of a straight line?

A slope tells how vertical a line is.

The more the slope is, the more the line is vertical. When the slope is zero, the line is horizontal.

When you graph the following lines, the set of equations that has (3, 1) as its solution are lines A and D.

We can see that both lines pass through the coordinate (3, 1).

For line A, we have (-3,4) and (9, -2)

[tex]y - y_1 = m(x - x_1)\\y - 4 = \dfrac{-2 - 4}{9 -(-3)}(x - (-3))\\y - 4 = -(1/2)(x+3)\\2y - 8 = -x - 3\\2y = -x + 5[/tex]

now, substitute (3, 1)

2(1) = -3 + 5

2 = 2

Line D passes through points 2, negative 2 and 5, and 6.

[tex]y +2 = 8/3(x -2)\\\\3y + 6 = 8x - 16\\\\3y - 8x = 10[/tex]

now, substitute (3, 1)

3(1) - 8(3) = 10

10 = 10

Learn more about parallel lines here:

https://brainly.com/question/13857011

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