Respuesta :
check the picture below.
[tex]\bf 6x^2-2x+8=(2x-4)h\implies \cfrac{6x^2-2x+8}{2x-4}=h \\\\\\ \cfrac{3(2x^2-x+4)}{2(x-2)}=h\implies \cfrac{3(3x-4)(x+1)}{2(x-2)}=h[/tex]
[tex]\bf 6x^2-2x+8=(2x-4)h\implies \cfrac{6x^2-2x+8}{2x-4}=h \\\\\\ \cfrac{3(2x^2-x+4)}{2(x-2)}=h\implies \cfrac{3(3x-4)(x+1)}{2(x-2)}=h[/tex]
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