Respuesta :

crisforp
We have f(x) = 0;
Then x^2 - 1 - 2x - 2 = 0;
(x - 1)(x + 1) - 2(x + 1) = 0;
(x + 1)(x - 1 - 2) = 0;
(x + 1)(x - 3) = 0;
x + 1 = 0 or x - 3 = 0;
x = -1 or x = 3;
The zeroes of f are -1 and 3.

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