check the picture below.
so the pyramid is really just 4 triangular faces with a base of 5 and a height of 8, and a 5x5 square at the bottom, now, if we just get the area of all 4 triangles and the square, sum them up, that's the area of the pyramid in feet.
[tex]\bf \stackrel{\textit{4 triangles}}{4\left[ \cfrac{1}{2}(5)(8) \right]}~~+~~\stackrel{\textit{square}}{5\cdot 5}\implies 80+25\implies 105~feet^2
\\\\\\
\stackrel{\textit{there are }9ft^2\textit{ in }1yd^2}{105\underline{ft^2}\cdot \cfrac{yd^2}{9\underline{ft^2}}\implies \cfrac{105}{9}yd^2\implies \cfrac{35}{3}yd^2\implies 11\frac{2}{3}~yd^2}[/tex]
