Respuesta :
d = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
The first cars speed is X miles per hour.
The 2nd cars speed is X + 12 miles per hour
X + X +12 = 232 / 2
2x +12 = 116
2x = 116-12
2x = 104
x = 104 / 2
x = 52
x+12 = 52+12 = 64
The 2 cars are driving 52 and 64 miles per hour
The 2nd cars speed is X + 12 miles per hour
X + X +12 = 232 / 2
2x +12 = 116
2x = 116-12
2x = 104
x = 104 / 2
x = 52
x+12 = 52+12 = 64
The 2 cars are driving 52 and 64 miles per hour