The gravitational attraction between the Earth and the Hubble telescope is given by:
[tex] F=G\frac{M m}{r^2} [/tex]
where
G is the gravitational constant
M is the Earth's mass
m is the Hubble mass
r is the distance of the Hubble telescope from the earth's center
By rearranging the equation and substituting the numbers given by the problem, we find the mass of the telescope:
[tex] m=\frac{F r^2}{GM}=\frac{(9.21 \cdot 10^4 N)(6.94 \cdot 10^6 m)^2}{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} )(5.98 \cdot 10^{24}kg) } = 11121 kg [/tex]
