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The point-slope form of the equation of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). What is the standard form of the equation for this line?

Respuesta :

sqdancefan

Multiply by 4 and rearrange.

... 4y -4 = x - 12

... -4 = x - 4y - 12 . . . . . . subtract 4y

... x - 4y = 8 . . . . . . . . . . add 12. This is standard form.

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haileeee12

Answer:

Step-by-step explanation:

A) x-4y=8

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