how can a translation and reflection be used to map HJK to LMN?
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Answer:
The figure HJK translated upward and then reflected across the vertical line which is passes through the mid point of JN.
Step-by-step explanation:
Given information:
[tex]JK=MN[/tex]
[tex]\angle K=\angle N[/tex]
[tex]HK=LN[/tex]
By SAS postulate,
[tex]\triangle HJK=\triangle LMN[/tex]
Translation is a rigid transformation, it means the size and shape of the figure is same as the image but it moves from one place to another place.
The triangle LMN is slightly above than HJK ,so the figure HJK translated upward.
Now triangle HJK is mirror image of triangle LMN across the vertical line which is passes through the mid point of JN. So, the triangle reflected across the vertical line which is passes through the mid point of JN.
Therefore the figure HJK translated upward and then reflected across the vertical line which is passes through the mid point of JN.