Hello!
Data:
Vo (initial volume) = 237.54 mL
V (final volume) = ?
To (initial temperature) = 45 ºC (to Kelvin)
T (final temperature) = 65 ºC (to Kelvin)
Note: In gas studies the Kelvin scale (K) is used
To (initial temperature) = TC + 273
To (initial temperature) = 45 + 273
To (initial temperature) = 318
T (final temperature) = TC + 273
T (final temperature) = 65 + 273
T (final temperature) = 338
We have an isobaric transformation, that is, its pressure remains constant, if it increases the temperature the volume also increases, applying the data to the formula, we have:
[tex] \dfrac{V_0}{T_0} = \dfrac{V}{T} [/tex]
[tex]\dfrac{273.54}{318} = \dfrac{V}{338} [/tex]
[tex]318*V = 273.54*338[/tex]
[tex]318V = 92456.52[/tex]
[tex]V = \dfrac{92456.52}{318} [/tex]
[tex]\boxed{\boxed{V \approx 290.74\:mL}}\end{array}}\qquad\checkmark[/tex]
I hope this helps. =)
