Respuesta :
The following equation is an equation of a line in slope-intercept form
y = mx + b
(x,y) represents one of the points lies on the line, m represents the slope, b represents the y-intercept
The line above passes through the points:
(x₁,y₁) = (-5,0)
(x₂,y₂) = (-1,-8)
1. Find the slope with slope formula
m = [tex] \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
m = [tex] \dfrac{-8-0}{-1-(-5)} [/tex]
m = [tex] \dfrac{-8}{-1+5} [/tex]
m = [tex] \dfrac{-8}{4)} [/tex]
m = -2
The slope is -2
2. Find the y-intercept by subtituting (x,y) = (-5,0) and m = -2 into slope-intercept form
y = mx + b
0 = -2(-5) + b
0 = 10 + b
b = -10
The y-intercept is -10
3. Therefore the line equation will be
y = mx + b
y = -2x - 10
y = mx + b
(x,y) represents one of the points lies on the line, m represents the slope, b represents the y-intercept
The line above passes through the points:
(x₁,y₁) = (-5,0)
(x₂,y₂) = (-1,-8)
1. Find the slope with slope formula
m = [tex] \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
m = [tex] \dfrac{-8-0}{-1-(-5)} [/tex]
m = [tex] \dfrac{-8}{-1+5} [/tex]
m = [tex] \dfrac{-8}{4)} [/tex]
m = -2
The slope is -2
2. Find the y-intercept by subtituting (x,y) = (-5,0) and m = -2 into slope-intercept form
y = mx + b
0 = -2(-5) + b
0 = 10 + b
b = -10
The y-intercept is -10
3. Therefore the line equation will be
y = mx + b
y = -2x - 10
Answer:
the equation of the line in slope-intercept form is
y = –2x – 10