From the histogram, we have to calculate P(4<X≤12)
In order to calculate thi, we will break this down to two probabilties
P (4<X[tex] \leq [/tex]8)
and
P (8<X[tex] \leq [/tex]12)
The probability P (4<X[tex] \leq [/tex]8) refers to the second bar on the histogram
The probability P (8<X[tex] \leq [/tex]12) refers to the third bar on the histogram
We add the two probabilities to get the final answer
P (4<X[tex] \leq [/tex]8) = 0.1
P (8<X[tex] \leq [/tex]12) = 0.35
Therefore, P(4<X≤12) = 0.1 + 0.35 = 0.45
P(4<X≤12) = 0.45