Respuesta :

first off, let's convert the decimals to fractions, and we'll do so by "using as many zeros at the bottom as there are decimals, and lose the dot", 

[tex]\bf y=0.\underline{2} x-0.\underline{3}\implies y=\cfrac{02}{1\underline{0}}x-\cfrac{03}{1\underline{0}}\implies y=\cfrac{2x}{10}-\cfrac{3}{10} \\\\\\ \textit{and now we'll multiply both sides by the }\stackrel{LCD}{10} \\\\\\ 10(y)=10\left( \cfrac{2x}{10}-\cfrac{3}{10} \right)\implies 10y=2x-3 \\\\\\ \stackrel{standard~form}{-2x+10y=-3}[/tex]
fichoh

The standard form of a linear equation is expressed in the form x + y = c. Hence, the required equation is - 2x + 10y = - 3

Given the linear equation written in slope - intercept form :

  • y = 0.2x - 0.3

Multiply both left and right hand side of the equation by 10 :

  • 10y = 2x - 3

Subtract 2x from both sides to isolate the constant term, 3 :

  • -2x + 10y = 2x - 3 - 2x

Hence, we have ;

  • -2x + 10y = - 3

Therefore, the standard form of the equation is - 2x + 10y = - 3

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