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jaguarnegro962oxdsot
V= area of the base * height
Finding the height of the pyramid: use Pythagorean theorem
First divide the base edge by 2. That way you can use the theorem
30^2 +b^2 = 50^2
900+b^2= 2500
900-900+b^2=2500-900
b^2=1600
[tex] \sqrt{b {}^{2} } = \sqrt{1600} [/tex]
b=40 in
Now on to the volume
V=60*60*40
V=3600*30
V=144000 in cubed
The volume is 140,000 inches cubed
JeanaShupp

Answer: 48000 cubic inches

Step-by-step explanation:

Given: Slant height of pyramid (l)= 50 in.

Base edge (s)= 60 in.

Let h be the height of the pyramid, the to find the height of the pyramid we consider a portion of pyramid as right triangle, so by Pythagoras theorem we have

[tex]h=\sqrt{l^2-(\dfrac{s}{2})^2}\\\\\Rightarrow\ h=\sqrt{(50)^2-(\dfrac{60}{2})^2}\\\\\Rightarrow\ h=40\ in.[/tex]

The volume of square pyramid is given by :-

[tex]V=\dfrac{1}{3}s^2h\\\\\Rightarrow\ V=\dfrac{1}{3}\times(60)^2(40)\\\\\Rightarrow\ V=48000\ in.^3[/tex]

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