Answer:
Net force, F' = 9 N (down)
Explanation:
It is given that, a ball is dropped from the top of a building.
The gravitational force acting on the ball, F = 10 N (down)
The air resistance acting on the ball, f = 1 N (up)
We need to find the magnitude of net force acting on the ball. The net force is given by :
[tex]F'=F-f[/tex]
[tex]F'=10-1[/tex]
F' = 9 N
So, the net force acting on the ball is 9 N in downward direction. Hence, this is the required solution.
The net force on the object is 9N down.
The given parameters;
gravitational force, Fg = 10 N
force of air resistance, Fr = 1 N
The net force on an object is defined as the change in the total force on the object.
Assuming the downward motion = positive direction
the downward motion = air resistance = negative direction
The net force on the object is calculated as follows;
[tex]\Sigma F_{net} = F_{down} - F_{up}\\\\\Sigma F_{net} = 10 N - 1 N\\\\\Sigma F_{net} = 9\ N \ down[/tex]
Thus, the net force on the object is 9N down.
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