Consider these chemical equations. N2(g) + 3H2(g) → 2NH3(g) C(s) + 2H2(g) → CH4(g) 4H2(g) + 2C(s) + N2(g) → 2HCN(g) + 3H2(g) Which equation(s) do you need to reverse in order to calculate the overall equation for the formation of HCN and H2 from NH3 and CH4? Check all that apply. N2(g) + 3H2(g) mr003-1.jpg 2NH3(g) C(s) + 2H2(g) mr003-2.jpg CH4(g) 4H2(g) + 2C(s) + N2(g) mr003-3.jpg 2HCN(g) + 3H2(g) What must you do before adding the equations?

The equation to be reversed to obtain the overall equation has been equation 2, i.e. [tex]\rm C\;+\;2\;H_2\;\rightarrow\;CH_4[/tex] and equation 1 i.e. [tex]\rm N_2\;+\;3\;H_2\;\rightarrow\;2\;NH_3[/tex]. Thus, option A and B are correct.

The chemical equation has been defined as the reaction for the formation of products in the chemical symbolization. The addition of multiple steps in the correct sequence has been resulted in the formation of resultant reaction.

Chemical equations

The given chemical equations have been given in the image attached.

The final reaction to be obtained has been given in the image attached.

For the following reaction, the methane and ammonia has been the reactant for the formation of carbon and hydrogen.

In equation 2 the methane has been in the product side, and in equation 1 ammonia has been on the product side.

Thus, equation 2, i.e. [tex]\rm C\;+\;2\;H_2\;\rightarrow\;CH_4[/tex] and equation 1 i.e. [tex]\rm N_2\;+\;3\;H_2\;\rightarrow\;2\;NH_3[/tex] has to be reversed to obtain the overall equation. Thus, option A and B are correct.

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